Mar 7, 2013 #1 S Sdfgsdfg New member Mar 7, 2013 0 0 0 A DVD club charges a $15 membership fee and $3 for each DVD you rent. Another DVD club charges a $10 membership fee and $4 for each DVD rental. For what number of DVD rentals is the cost of both clubs the same?
A DVD club charges a $15 membership fee and $3 for each DVD you rent. Another DVD club charges a $10 membership fee and $4 for each DVD rental. For what number of DVD rentals is the cost of both clubs the same?
May 21, 2013 #2 R rosa Member Apr 16, 2008 81 0 6 DVD Club 1: DVD Club 2: 15+3=18 (Membership+1 DVD) 10+4=14 18+3=21 (2 DVD's) 14+4=18 21+3=24 (3 DVD's) 18+4=22 24+3=27 (4 DVD's) 22+4=26 27+3=30 (5 DVD's) 26+4=30 5 DVD RENTAL.
DVD Club 1: DVD Club 2: 15+3=18 (Membership+1 DVD) 10+4=14 18+3=21 (2 DVD's) 14+4=18 21+3=24 (3 DVD's) 18+4=22 24+3=27 (4 DVD's) 22+4=26 27+3=30 (5 DVD's) 26+4=30 5 DVD RENTAL.
Jun 8, 2013 #3 L llaffer New member Jun 8, 2008 19 0 1 Let: n = number of rentals club 1 is $15 plus $3 per rental, so ... 15 + 3n club 2 is $10 plus $4 per rental, so ... 10 + 4n Where do they meet? set one expression equal to the other and solve for n... 15 + 3n = 10 + 4n 5 = n At 5 rentals, the prices for both clubs are the same.
Let: n = number of rentals club 1 is $15 plus $3 per rental, so ... 15 + 3n club 2 is $10 plus $4 per rental, so ... 10 + 4n Where do they meet? set one expression equal to the other and solve for n... 15 + 3n = 10 + 4n 5 = n At 5 rentals, the prices for both clubs are the same.