[-e^(-x)] between 0 and +infinity
= 1 - (e^(-infinity))
Right? My mind has gone blank. What do I do now?
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[-e^(-x)] between 0 and +infinity
= 1 - (e^(-infinity))
Right? My mind has gone blank. What do I do now?
If a function is raised to a negative (-) power, it becomes a reciprocal of the function i.e. x^-2 is 1/x^2
So, e^-(infinity) is actually 1/e^infinity,
Which is 1/infinity, which tends to zero.
Hence, the answer is 1.
If a function is raised to a negative (-) power, it becomes a reciprocal of the function i.e. x^-2 is 1/x^2
So, e^-(infinity) is actually 1/e^infinity,
Which is 1/infinity, which tends to zero.
Hence, the answer is 1.
thanks! that was helpful
the integral of things that tend to 0 is not always 1..............................
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