lillies_o_thorns
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- Sep 24, 2008
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lim x--> infinity sin((x-1)/(2+x^2))
I'm not sure how to handle trig function limits. I used my graphing calc to see what the function would look like, and it seems to go to zero, but I need to show steps as to how I got my answer.
What I did was divide top and bottom of the bracketed part by x^2 and then just used one of the limit laws to determine that it would be:
lim x--> infinity sin ((0-0)/(0+1))
sin (0/1)=0
So am I right to say at the limit approaches zero as x approaches infinity? Did I do the steps properly?
What would change if the limit instead was sin ((x^2+1)/(x+1)) ?
I'm not sure how to handle trig function limits. I used my graphing calc to see what the function would look like, and it seems to go to zero, but I need to show steps as to how I got my answer.
What I did was divide top and bottom of the bracketed part by x^2 and then just used one of the limit laws to determine that it would be:
lim x--> infinity sin ((0-0)/(0+1))
sin (0/1)=0
So am I right to say at the limit approaches zero as x approaches infinity? Did I do the steps properly?
What would change if the limit instead was sin ((x^2+1)/(x+1)) ?