3rd dimnsn, future is in 4th dim? As 3 dimensional beings percieving time, we cannot "fit" in the present, and only truly experience the future.
Does that make any sense; discuss why or why not please.
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3rd dimnsn, future is in 4th dim? As 3 dimensional beings percieving time, we cannot "fit" in the present, and only truly experience the future.
Does that make any sense; discuss why or why not please.
If the magnitude of the velocity vector remains the same, and only the direction changes, you can get the magnitude of h like that:
h = r x v
->
|h| = |r| * |v| * cos(a)
Your orbit energy, remains constant, as your radius and the magnitude of the velocity remains constant.
So, your semi-major axis remains constant, but your eccentricity should change.
You want to change the eccentricity as such, that your periapsis distance is half the semi-major axis.
r/2 = Sma/2 = Sma(1-e) ->
0.5 = e
So, the question is now: Which angle is needed, so that e is 0.5? We can get this over h.
|h| = sqrt(p*µ) = sqrt(Sma(1-e²)/µ)
|h| at a circular orbit is, as you have initially is:
|h(0)| = sqrt(Sma/µ)
You want:
|h(0.5)| = sqrt(0.75Sma/µ)
we remember from the beginning:
|h(0.5)|/|h(0)| = cos(a)/cos(0) = cos(a)
sqrt(0.75Sma/µ)/sqrt(Sma/µ) = sqrt(0.75) = cos(a)
cos(a) = sqrt(3/4)
a = 30°
If the magnitude of the velocity vector remains the same, and only the direction changes, you can get the magnitude of h like that:
h = r x v
->
|h| = |r| * |v| * cos(a)
Your orbit energy, remains constant, as your radius and the magnitude of the velocity remains constant.
So, your semi-major axis remains constant, but your eccentricity should change.
You want to change the eccentricity as such, that your periapsis distance is half the semi-major axis.
r/2 = Sma/2 = Sma(1-e) ->
0.5 = e
So, the question is now: Which angle is needed, so that e is 0.5? We can get this over h.
|h| = sqrt(p*µ) = sqrt(Sma(1-e²)/µ)
|h| at a circular orbit is, as you have initially is:
|h(0)| = sqrt(Sma/µ)
You want:
|h(0.5)| = sqrt(0.75Sma/µ)
we remember from the beginning:
|h(0.5)|/|h(0)| = cos(a)/cos(0) = cos(a)
sqrt(0.75Sma/µ)/sqrt(Sma/µ) = sqrt(0.75) = cos(a)
cos(a) = sqrt(3/4)
a = 30°
We use 3 numbers, to locate an object space, ONLY 3 numbers are necessary to locate something in space. Therefore we say that space has 3 dimensions. We can use more numbers, but ONLY 3 are necessary.
If the object has limited existance, we can use a forth number to locate it in time also. Ergo, we can say there are 4 dimensions.
Every dimension consists of 2 directions, we can go forward or backwards along a dimension. If I go North, that is one direction, if I go South, that is another direction. But North and South together would be a dimension.
You can have an infinite number of dimensions in space alone, but you will still ONLY need 3 numbers to locate an object in space, ergo, we say there are 3 dimensions.
We can only go forward in time, not backwards, ergo, it may be, that time is not a full dimension, but only one direction, towards the future.
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